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c++语句switch语句
The error: case label not within a switch statement occurs in C language with switch case statement, when switch (variable/value) statement is terminated by the semicolon (;).
错误:当switch(变量/值)语句由分号( ; )终止时,C语言中的case标签使用switch case语句以C语言出现。
Example:
例:
#includeint main(void) { int choice = 2; switch(choice); { case 1: printf("Case 1\n"); break; case 2: printf("Case 2\n"); break; case 3: printf("Case 3\n"); break; case 4: printf("Case 4\n"); break; default: printf("Case default\n"); } return 0;}
Output
输出量
prog.c: In function ‘main’:prog.c:9:6: error: case label not within a switch statement case 1: ^~~~prog.c:11:10: error: break statement not within loop or switch break; ^~~~~prog.c:12:6: error: case label not within a switch statement case 2: ^~~~prog.c:14:10: error: break statement not within loop or switch break; ^~~~~prog.c:15:6: error: case label not within a switch statement case 3: ^~~~prog.c:17:10: error: break statement not within loop or switch break; ^~~~~prog.c:18:6: error: case label not within a switch statement case 4: ^~~~prog.c:20:10: error: break statement not within loop or switch break; ^~~~~prog.c:21:6: error: ‘default’ label not within a switch statement default: ^~~~~~~
How to fix?
怎么修?
See the statement switch(choice); it is terminated by semicolon (;) – it must not be terminated. To fix this error, remove semicolon after this statement.
参见语句switch(choice); 它以分号( ; )终止–一定不能终止。 要解决此错误,请在此语句后删除分号。
Correct code:
正确的代码:
#includeint main(void) { int choice = 2; switch(choice) { case 1: printf("Case 1\n"); break; case 2: printf("Case 2\n"); break; case 3: printf("Case 3\n"); break; case 4: printf("Case 4\n"); break; default: printf("Case default\n"); } return 0;}
Output
输出量
Case 2
翻译自:
c++语句switch语句
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